n^2+4n-1=4

Solution for n^2+4n-1=4 equation:

Simplifying
n2 + 4n + -1 = 4

Reorder the terms:
-1 + 4n + n2 = 4

Solving
-1 + 4n + n2 = 4

Solving for variable 'n'.

Reorder the terms:
-1 + -4 + 4n + n2 = 4 + -4

Combine like terms: -1 + -4 = -5
-5 + 4n + n2 = 4 + -4

Combine like terms: 4 + -4 = 0
-5 + 4n + n2 = 0

Factor a trinomial.
(-5 + -1n)(1 + -1n) = 0

Subproblem 1
Set the factor '(-5 + -1n)' equal to zero and attempt to solve:

Simplifying
-5 + -1n = 0

Solving
-5 + -1n = 0

Move all terms containing n to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -1n = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -1n = 0 + 5
-1n = 0 + 5

Combine like terms: 0 + 5 = 5
-1n = 5

Divide each side by '-1'.
n = -5

Simplifying
n = -5
Subproblem 2
Set the factor '(1 + -1n)' equal to zero and attempt to solve:

Simplifying
1 + -1n = 0

Solving
1 + -1n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1n = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1n = 0 + -1
-1n = 0 + -1

Combine like terms: 0 + -1 = -1
-1n = -1

Divide each side by '-1'.
n = 1

Simplifying
n = 1
Solution
n = {-5, 1}